Why is the vapour pressure of an aqueous solution of glucose lower than that of water?
Why is the vapour pressure of an aqueous solution of glucose lower than that of water?

An example of water and glucose can be taken to illustrate this. In water, the surface of this liquid will settle with water molecules. If we put glucose into it, some of these areas will be inhabited by glucose molecules. Thus, the amount of soluble molecule will come out of the surface and thus the pressure of the vapor is also reduced.