SO2 + 2H2S → 2H2O +3S
In the reaction above, H2S got oxidized as Hydrogen was removed from the molecule while SO2 got reduced because Oxygen was removed.
When SO2 gas is passed through saturated solution of H2S, the following reaction occurs:
![\[\mathbf{S}{{\mathbf{O}}_{\mathbf{2}}}~+\text{ }\mathbf{2}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{S}\text{ }\to \text{ }\mathbf{2}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{O}\text{ }+\mathbf{3S}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f253585babb374c2b6e61729cf8a446f_l3.png "Rendered by QuickLaTeX.com")
In this reaction, which substance is oxidized and which one is reduced?