As per the inquiry,
We get the figure given underneath,
We realize that,
Complete surface space of shape framed = Curved space of first cone + Curved surface space of second cone
Since, the two cones are indistinguishable,
We have,
All out surface space of shape framed = Curved space of first cone + Curved surface space of the subsequent cone
= 2(Surface space of cone)
We additionally realize that,
Surface space of cone = πrl, where r = range and l = incline stature
What’s more, the absolute Surface space of shape so framed = 2πrl
Given in the inquiry that,
Range, r = 8 cm
Tallness, h = 15 cm
Consequently,
Region = Curved space of first cone + Curved surface space of the subsequent cone
= 2 (Surface space of the cone)
![\[=\text{ }2\text{ }\times \text{ }\pi rl\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-cc2a4f76bacab33f25ff4c394e6d5c77_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }2\text{ }\times \text{ }\pi \text{ }\times \text{ }r\text{ }\times \text{ }\surd \left( r2\text{ }+\text{ }h2 \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7ade199c431cb8a5c20ecb9246ad70c7_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }2\text{ }\times \text{ }\left( 22/7 \right)\text{ }\times \text{ }8\text{ }\times \text{ }\surd \left( 82\text{ }+\text{ }152 \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e130f5ffb145925a7fc8663730023967_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }50.28\text{ }\times \text{ }\surd 289\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1695d374e64982a339ba673aa75c509c_l3.png "Rendered by QuickLaTeX.com")
= 854.85 cm2
= 855 cm2 (approx)
Consequently, the surface space of shape so framed is 855cm2.