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Home » The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.
The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.
CBSE | Class 10 | Exercise 4.3 | Quadratic Equations
The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.

Solution:

Let us say, the shorter side of the rectangle be x m.

Then, larger side of the rectangle = (x + 30) m

Ncert solutions class 10 chapter 4-6

As given, the length of the diagonal is = x + 30 m

Therefore,

Ncert solutions class 10 chapter 4-7

\Rightarrow ~{{x}^{2}}~+\text{ }{{\left( x~+\text{ }30 \right)}^{2}}~=\text{ }{{\left( x~+\text{ }60 \right)}^{2}}

\Rightarrow ~{{x}^{2}}~+~{{x}^{2}}~+\text{ }900~+\text{ }60x~=~{{x}^{2}}~+\text{ }3600~+\text{ }120x

\Rightarrow ~{{x}^{2}}~\text{ }60x~\text{ }2700\text{ }=\text{ }0

\Rightarrow ~{{x}^{2}}~\text{ }90x~+\text{ }30x~\text{ }2700\text{ }=\text{ }0

\Rightarrow ~x\left( x~\text{ }90 \right)~+\text{ }30\left( x~-90 \right)\text{ }=\text{ }0

\Rightarrow \left( x~\text{ }90 \right)\left( x~+\text{ }30 \right)\text{ }=\text{ }0

\Rightarrow ~x~=\text{ }90,\text{ }-30

However, side of the field cannot be negative. Therefore, the length of the shorter side will be 90 m.

and the length of the larger side will be (90 + 30) m = 120 m.

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