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Prove that (4 – 5√2) is irrational.

Answer:

Consider,

x = 4 – 5√2 be a rational number.

x = 4 – 5√2

x2 = (4 – 5√2)2

x2 = 42 + (5√2)2 – 2(4) (5√2)

x2 = 16 + 50 – 40√2

x2 – 66

x2 = – 40√2

=>

=> √2

x is a rational number, xis also a rational number.

⇒ 66 – x

2 is a rational number

is a rational number

√2 – rational number

But √2 is an irrational number, which is a contradiction.

The assumption is wrong.

Hence, (4 – 5√2) is an irrational number.