(A) In bromoethane and chloroethane mixture intermolecular interactions of A–A and B–B type are nearly the same as A–B type interactions.

(B) In ethanol and acetone mixture A–A or B–B type intermolecular interactions are stronger than A–B type interactions.

(C) In chloroform and acetone mixture A–A or B–B type intermolecular interactions are weaker than A–B type interactions.

(i) Solution (B) and (C) will follow Raoult’s law.

(ii) Solution (A) will follow Raoult’s law.

(iii) Solution (B) will show a negative deviation from Raoult’s law.

(iv) Solution (C) will show a positive deviation from Raoult’s law

Correct Answer: (ii) Solution (A) will follow Raoult’s law

Explanation: Raoult’s law is an important law of thermodynamics. It states that the partial pressure of each component of a suitable liquid would be equal to the pressure of a vapor content of pure material multiplied by its molecular fraction in a fraction. Here, solution 1 will follow Raoult’s rule because the solution made after mixing will be fine. And so, it will not show any deviation as the intermolecular strength after mixing will also be the same.