The capacitance of the capacitor is given by $\mathrm{C}=2 \mu \mathrm{F}$
Displacement current is given as $I_{d}=1 \mathrm{~mA}$
Hence, Charge in capacitor will be,
$q=C V$
$\mathrm{dV} / \mathrm{dt}=500 \mathrm{~V} / \mathrm{s}$
You are given a $2\mu F$ parallel plate capacitor. How would you establish an instantaneous displacement current of $1 \mathrm{~mA}$ in the space between its plates?
You are given a $2\mu F$ parallel plate capacitor. How would you establish an instantaneous displacement current of $1 \mathrm{~mA}$ in the space between its plates?