Hence identify the exact logic operation carried out by this circuit.
Solution:
From the figure, we know $B$ is the output, $A$ being the input.
Hence, the output can be written as:
$Y=\overline{A \cdot A}=\bar{A}+\bar{A}=\bar{A}$
We can make the truth table for equation (1) as:
| A | $Y=\overline{A}$ |
| 0 | 1 |
| 1 | 0 |
Below is the symbol of the NOT gate:
