Answer:
When $D_2SO_4$ interacts with $BaO_2, D_2O_2$ is generated, which is then followed by the formation of barium sulphate ($BaSO_4$).
In the presence of $D_2SO_4 + BaO_2 → D_2O_2 + BaSO_4$
Answer:
When $D_2SO_4$ interacts with $BaO_2, D_2O_2$ is generated, which is then followed by the formation of barium sulphate ($BaSO_4$).
In the presence of $D_2SO_4 + BaO_2 → D_2O_2 + BaSO_4$