Work out the volume involved by 8.8 g of CO2 at 31.1°C and 1 bar pressure. \[R\text{ }=\text{ }0.083\text{ }bar\text{ }dm3\text{ }K1\text{ }mol1.\]

solution:

\[\begin{array}{*{35}{l}}

~  \\

pVM\text{ }=\text{ }mRT  \\

~  \\

V=\text{ }mRT/Mp  \\

\end{array}\]

Here,

 

\[\begin{array}{*{35}{l}}

m\text{ }=\text{ }8.8\text{ }g  \\

~  \\

R\text{ }=\text{ }0.083\text{ }bar\text{ }LK1\text{ }mol1  \\

~  \\

T\text{ }=\text{ }31.1{}^\circ C\text{ }=\text{ }304.1\text{ }K  \\

~  \\

M\text{ }=\text{ }44\text{ }g\text{ }p\text{ }=\text{ }1\text{ }bar  \\

\end{array}\]

In this manner, the volume involved is 5.05 L.