Following are the steps of Construction:
(i) Consider
\[AB\text{ }=\text{ }5.1\text{ }cm.\]
(ii) At the point A, radius
\[=\text{ }5.6/2\text{ }=\text{ }2.8\text{ }cm\]
At the point B, radius
\[=\text{ }7.0/2\text{ }=\text{ }3.5\text{ }cm\]
Construct two arcs which intersect each other at the point O.
(iii) Now join AO and produce it to point C such that
\[OC\text{ }=\text{ }AD\text{ }=\text{ }2.8\text{ }cm\]
and join BO and produce it to D such that
\[BO\text{ }=\text{ }OD\text{ }=\text{ }3.5\text{ }cm.\]
(iv) Join BC, CD and DA
now,
ABCD is a parallelogram.
(v) Construct the angle bisector of ∠ABC which intersects CD at P.
P is the required point equidistant from AB and BC.