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Without using set square or protractor, construct the parallelogram ABCD in which AB = 5.1 cm, the diagonal AC = 5.6 cm and diagonal BD = 7 cm. Locate the point P on DC, which is equidistant from AB and BC
Without using set square or protractor, construct the parallelogram ABCD in which AB = 5.1 cm, the diagonal AC = 5.6 cm and diagonal BD = 7 cm. Locate the point P on DC, which is equidistant from AB and BC
Class 10 | Exercise 1 | ICSE | Locus | Maths | ML Aggarwal
Without using set square or protractor, construct the parallelogram ABCD in which AB = 5.1 cm, the diagonal AC = 5.6 cm and diagonal BD = 7 cm. Locate the point P on DC, which is equidistant from AB and BC

Following are the steps of Construction:

ML Aggarwal Solutions for Class 10 Chapter 14 Image 44

(i) Consider

\[AB\text{ }=\text{ }5.1\text{ }cm.\]

(ii) At the point A, radius

\[=\text{ }5.6/2\text{ }=\text{ }2.8\text{ }cm\]

At the point B, radius

\[=\text{ }7.0/2\text{ }=\text{ }3.5\text{ }cm\]

Construct two arcs which intersect each other at the point O.

(iii) Now join AO and produce it to point C such that

\[OC\text{ }=\text{ }AD\text{ }=\text{ }2.8\text{ }cm\]

and join BO and produce it to D such that

\[BO\text{ }=\text{ }OD\text{ }=\text{ }3.5\text{ }cm.\]

(iv) Join BC, CD and DA

now,

ABCD is a parallelogram.

(v) Construct the angle bisector of ∠ABC which intersects CD at P.

P is the required point equidistant from AB and BC.

i

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