The given statement is true
Explanation:
Let \[r\] be the radius of circle and is equal \[a\] cm
Therefore, Diameter of the circle = d = \[2\times Radius\] = \[2a\] cm
From the question we got that circle is inscribed in the square,
Therefore, Side of a square = Diameter of circle = \[2a\] cm
Perimeter of a square = \[4\times (side)\] = \[4\times 2a\] = \[8a\] cm
Therefore, the perimeter of a square circumscribing a circle of radius \[a\] cm is \[8a\] cm.