The chemical in question is glucose pentaacetate. The presence of a free –C=O group in glucose indicates the presence of a free carbonyl group, as does the synthesis of oxime from glucose. Because the supplied chemical lacks a free carbonyl group, it cannot form an oxime when reacting with hydroxylamine.
Why does compound (A) give below not form an oxime?
Why does compound (A) give below not form an oxime?