$ 1.\,\,{{C}_{5}}{{H}_{5}}N{{H}^{+}}Cr{{O}_{3}}Cl $

$ 2.\,\,{{K}_{2}}C{{r}_{2}}{{O}_{7}}/dil.\,{{H}_{2}}S{{O}_{4}} $

$ 3.\,\,dil.\,HN{{O}_{3}} $

$ 4.\,\,Cr{{O}_{3}} $

Solution: $ 1.\,\,{{C}_{5}}{{H}_{5}}N{{H}^{+}}Cr{{O}_{3}}Cl $

Pyridinium Chlorochromate (PCC)

Primary alcohols can be converted to aldehydes, and secondary alcohols can be converted to ketones, using PCC. Because the starting material is a secondary alcohol, the end product will be a ketone (a carbonyl () group with two other carbons connected to it).