(i) 2Mg(s) + O2(g) →2MgO(s)
(ii) C3H8(g) + O2(g) → CO2(g) + H2O(g)
(iii) P4(s) + 5O2(g) → P4O10(s)
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O (g)
Answer:
Correct Answer: (ii) C3H8(g) + O2(g) → CO2(g) + H2O(g)
Explanation: The number of atoms present in the reactant side is not equal to the number of atoms present in the product side.