Which of the following is a quadratic equation?
(a) $x^{3}-3 \sqrt{x}+2=0$
(b) $x+\frac{1}{x}=x^{2}$
(c) $x^{2}+\frac{1}{x^{2}}=5$
(d) $2 x^{2}-5 x=(x-1)^{2}$
Which of the following is a quadratic equation?
(a) $x^{3}-3 \sqrt{x}+2=0$
(b) $x+\frac{1}{x}=x^{2}$
(c) $x^{2}+\frac{1}{x^{2}}=5$
(d) $2 x^{2}-5 x=(x-1)^{2}$

(d) $2 x^{2}-5 x=(x-1)^{2}$
A quadratic equation is the equation with degree 2 .
$\begin{array}{l}
\because 2 x^{2}-5 x=(x-1)^{2} \\
\Rightarrow 2 x^{2}-5 x=x^{2}-2 x+1 \\
\Rightarrow 2 x^{2}-5 x-x^{2}+2 x-1=0
\end{array}$
$\Rightarrow x^{2}-3 x-1=0$, which is a quadratic equation