Answer is (b) $x^{3}-x^{2}=(x-1)^{3}$
$\begin{array}{l}
\because x^{3}-x^{2}=(x-1)^{3} \\
\Rightarrow x^{3}-x^{2}=x^{3}-3 x^{2}+3 x-1
\end{array}$
$\Rightarrow 2 x^{2}-3 x+1=0$, which is a quadratic equation
Which of the following is a quadratic equation?
(a) $\left(x^{2}+1\right)=(2-x)^{2}+3$
(b) $x^{3}-x^{2}=(x-1)^{3}$
(c) $2 x^{2}+3=(5+x)(2 x-3)$
(d) None of these
(a) $\left(x^{2}+1\right)=(2-x)^{2}+3$
(b) $x^{3}-x^{2}=(x-1)^{3}$
(c) $2 x^{2}+3=(5+x)(2 x-3)$
(d) None of these
Which of the following is a quadratic equation?
(a) $\left(x^{2}+1\right)=(2-x)^{2}+3$
(b) $x^{3}-x^{2}=(x-1)^{3}$
(c) $2 x^{2}+3=(5+x)(2 x-3)$
(d) None of these
(a) $\left(x^{2}+1\right)=(2-x)^{2}+3$
(b) $x^{3}-x^{2}=(x-1)^{3}$
(c) $2 x^{2}+3=(5+x)(2 x-3)$
(d) None of these