Solution:
When two different dice are thrown, the total number of outcomes = 36. Let E be the event of getting the sum of the numbers less than 7.
These numbers are (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2) and (5,1).
Number of favorable outcomes = 15
Thus, the probability of getting the sum of the numbers less than 7