Answer:
(a) Lead Nitrate
(b) Lead Iodide
(c) Formation of precipitate
(d)Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)
Answer:
(a) Lead Nitrate
(b) Lead Iodide
(c) Formation of precipitate
(d)Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)