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What is the probability that a leap year has 53 Sundays and 53 Mondays?

Given is a leap year which includes 52 weeks and two days

By using the formula of probability, we get,

P (E) = favourable outcomes / total possible outcomes

So, we have to find the probability of that remaining two days is Sunday and Monday

S = {MT, TW, WT, TF, FS, SSu, SuM}

n (S) = 7

E= {SuM}

n (E) = 1

P (E) = n (E) / n (S)

= 1 / 7