Solution: The answer is (d) 1 Ω
Resistance is maximized by connecting resistors in series.
$$
\begin{aligned}
& R =\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5} \
&=5 / 5 \
&=1 \Omega
\end{aligned}
$$
Solution: The answer is (d) 1 Ω
Resistance is maximized by connecting resistors in series.
$$
\begin{aligned}
& R =\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5} \
&=5 / 5 \
&=1 \Omega
\end{aligned}
$$