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What does the equation \[\left( a-b \right)\left( {{x}^{2}}~+\text{ }{{y}^{2}} \right)-2abx\text{ }=\text{ }0\] become if the origin is shifted to the point (ab / (a-b), 0) without rotation?
What does the equation \[\left( a-b \right)\left( {{x}^{2}}~+\text{ }{{y}^{2}} \right)-2abx\text{ }=\text{ }0\] become if the origin is shifted to the point (ab / (a-b), 0) without rotation?
Brief review of Cartesian System of Rectangular Coordinates | CBSE | Class 11 | Exercise 22.3 | Maths | RD Sharma
What does the equation \[\left( a-b \right)\left( {{x}^{2}}~+\text{ }{{y}^{2}} \right)-2abx\text{ }=\text{ }0\] become if the origin is shifted to the point (ab / (a-b), 0) without rotation?

Solution:

The above-given equation \[\left( a-b \right)\left( {{x}^{2}}~+\text{ }{{y}^{2}} \right)-2abx\text{ }=\text{ }0\] can be rewritten into a new equation by replacing x by [X + ab / (a-b)] and y by Y

RD Sharma Solutions for Class 11 Maths Chapter 22- image 22

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