What are the points on the y-axis whose distance from the line x/3 + y/4 = 1 is 4 units?
What are the points on the y-axis whose distance from the line x/3 + y/4 = 1 is 4 units?

Consider (0, b) as the point on the y-pivot whose separation from line \[\mathbf{x}/\mathbf{3}\text{ }+\text{ }\mathbf{y}/\mathbf{4}\text{ }=\text{ }\mathbf{1}\text{ }\mathbf{is}\text{ }\mathbf{4}\text{ }\mathbf{units}.\]

It very well may be composed as \[\mathbf{4x}\text{ }+\text{ }\mathbf{3y}\text{ }\text{ }\mathbf{12}\text{ }=\text{ }\mathbf{0}\text{ }\ldots \text{ }.\text{ }\left( \mathbf{1} \right)\]

By contrasting condition (1) to the overall condition of line\[\mathbf{Ax}\text{ }+\text{ }\mathbf{By}\text{ }+\text{ }\mathbf{C}\text{ }=\text{ }\mathbf{0}\] , we get

\[\mathbf{A}\text{ }=\text{ }\mathbf{4},\text{ }\mathbf{B}\text{ }=\text{ }\mathbf{3}\text{ }\mathbf{and}\text{ }\mathbf{C}\text{ }=\text{ }\text{ }\mathbf{12}\]

We realize that the opposite distance (d) of a line \[\mathbf{Ax}\text{ }+\text{ }\mathbf{By}\text{ }+\text{ }\mathbf{C}\text{ }=\text{ }\mathbf{0}\] from (x1, y1) is composed as

By cross augmentation

\[\mathbf{20}\text{ }=\text{ }\left| \mathbf{3b}\text{ }\text{ }\mathbf{12} \right|\]

We get

\[\mathbf{20}\text{ }=\text{ }\pm \text{ }\left( \mathbf{3b}\text{ }\text{ }\mathbf{12} \right)\]

Here \[\mathbf{20}\text{ }=\text{ }\left( \mathbf{3b}\text{ }\text{ }\mathbf{12} \right)\text{ }\mathbf{or}\text{ }\mathbf{20}\text{ }=\text{ }\text{ }\left( \mathbf{3b}\text{ }\text{ }\mathbf{12} \right)\]

It tends to be composed as

NCERT Solutions for Class 11 Maths Chapter 10 – Straight Lines image - 51

\[\mathbf{3b}\text{ }=\text{ }\mathbf{20}\text{ }+\text{ }\mathbf{12}\text{ }\mathbf{or}\text{ }\mathbf{3b}\text{ }=\text{ }-\text{ }\mathbf{20}\text{ }+\text{ }\mathbf{12}\]

So we get

\[\mathbf{b}\text{ }=\text{ }\mathbf{32}/\mathbf{3}\text{ }\mathbf{or}\text{ }\mathbf{b}\text{ }=\text{ }-\text{ }\mathbf{8}/\mathbf{3}\]

Henceforth, the necessary focuses are \[\left( \mathbf{0},\text{ }\mathbf{32}/\mathbf{3} \right)\text{ }\mathbf{and}\text{ }\left( \mathbf{0},\text{ }-\text{ }\mathbf{8}/\mathbf{3} \right).\]