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verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0
verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0
CBSE | Class 12 | Differential Equations | Exercise 9.2 | NCERT
verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0

Differentiating both sides with respect to x, we get,

NCERT Solutions for Class 12 Maths Chapter 9 - Image 14

y’ = -sinx

Then,

Substituting the values of y’ in the given differential equations, we get,

\[\begin{array}{*{35}{l}}

=\text{ }y\text{ }+\text{ }sinx  \\

=\text{ }-\text{ }sinx\text{ }+\text{ }sinx  \\

=\text{ }0  \\

\end{array}\]

= RHS

Therefore, the given function is a solution of the given differential equation.

i

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