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Verify $A(\operatorname{adj} \mathbf{A})=(\operatorname{adj} \mathbf{A}) \mathbf{A}=|\mathbf{A}| \mathbf{I}$ in $\left[\begin{array}{cc}2 & 3 \\ -4 & -6\end{array}\right]$

Let A = 

 adj. A = 

 A.(adj. A) = 

 =   …..(i)

Again  (adj. A). A = 

 =     …..(ii)

And  = 

Again      …..(iii)

 From eq. (i), (ii) and (iii)  A. (adj. A) = (adj. A). A =