Verify $A(\operatorname{adj} \mathbf{A})=(\operatorname{adj} \mathbf{A}) \mathbf{A}=|\mathbf{A}| \mathbf{I}$ in $\left[\begin{array}{ccc}1 & -1 & 2 \\ 3 & 0 & -2 \\ 1 & 0 & 3\end{array}\right]$ 3 years ago . Let A = = adj. A = A. (adj. A) = = = ……….(i) Again (adj. A). A = = = ……….(ii) And = Also = ……….(iii) From eq. (i), (ii) and (iii) A. (adj. A) = (adj. A). A =