Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xv) (32.15)^1/5
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xv) (32.15)^1/5

(xv) 

Let  ……….(i)

   = 

   ……….(ii)

Now, from eq. (i), 

  ……….(iii)

Here  and 

Then 

 = 

Since,  and  is approximately equal to  and  respectively.

 From eq. (ii),

 = 0.001875

Therefore, approximate value of  is 2 + 0.001875= 2.001875.