Option A:
Option B:
Option C:
Option D:
Solution:
The correct option is C
Electric field is given as $\mathrm{E}^{\prime} \infty \frac{\mathrm{E}_{0}}{\mathrm{~K}}$
As $\mathrm{K}_{1}<\mathrm{K}_{2}$ so $\mathrm{E}_{1}>\mathrm{E}_{2}$
Option A:
Option B:
Option C:
Option D:
Solution:
The correct option is C
Electric field is given as $\mathrm{E}^{\prime} \infty \frac{\mathrm{E}_{0}}{\mathrm{~K}}$
As $\mathrm{K}_{1}<\mathrm{K}_{2}$ so $\mathrm{E}_{1}>\mathrm{E}_{2}$