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Two numbers are in the ratio $7:10.$ If $8$ is added to each number, the ratiobecomes $3:4.$ Find the numbers.

The ratio is used for comparing two quantities of the sane kind.

The ratio formula for two numbers says a and b is given by a:b or a/b. When two or more such ratios are equal, they are said to be in proportion.

The concept of ratio and proportion is majorly based on ratios and fractions.  

Solution:

From the question it is given that,

Two numbers are in the ratio $7:10.$

Let us assume the two numbers be $7y$ and $10y.$

Then, $\left( 7y+8 \right)/\left( 10y\times 8 \right)={}^{3}/{}_{4}$

$28y+32=30x+24$

$2y=8$

$y=8/2$

$y=4$

So, $7y=7\times 4=28$

$10y=10\times 4=40$

Therefore, the two numbers are $28$and $40.$