Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed along with colourless common salt solution.
(a) What could the metals X and Y be?
(b) Write the name and formula of salt XSO4.
(c) Write the name and formula of salt Y2SO4.
(d) What is the name and formula of white precipitate Z?
(e) Write the name and formula of the salt which turns the solution green in the first case.
(a)Metal X is Copper and Metal Y is Sodium. Both produce sulphate salts on reaction.
(b) XSO4 is Copper sulphate, CuSO4 , the salt formed which is blue in colour.
(c) Y2SO4 is Sodium sulphate, Na2SO4 which is a colourless salt.
(d) Z is Barium sulphate, BaSO4 which is a white precipitate formed upon the reaction when barium chloride is added to copper sulphate and turns the solution green
(e) Copper chloride, CuCl2 is the salt having yellowish-brown colour which turns the solution green.
