Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is: \[\left( \mathbf{iii} \right)\] less than or equal to \[\mathbf{12}\]

Solution:

\[\left( iii \right)\] All the outcomes are favourable to the event \[E\text{ }=\]‘sum of two numbers \[\le ~12\]

Thus, \[P\left( E \right)\text{ }=\text{ }n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }36/36\text{ }=\text{ }1\]