\[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{6}}}\]
As per the inquiry,
A line portion \[AB\]in the proportion \[5:7\]
Along these lines,\[~A:B\text{ }=\text{ }5:7\]
Steps of development:
- Draw a beam \[AX,\]an intense point \[BAX.\]
- Draw a beam\[BY\text{ }||AX\], \[point\text{ }ABY\text{ }=\text{ }point\text{ }BAX.\]
- Presently, find the focuses \[A1,A2,A3,A4\text{ }and\text{ }A5\]on \[AX\]and\[~B1,B2,B3,B4,B5\text{ }and\text{ }B6\]
\[\left( Since\text{ }A:B\text{ }=\text{ }5:7 \right)\]
- Join\[{{A}_{5}}{{B}_{6}}.\]
\[{{A}_{5}}{{B}_{6}}.\]meet \[AB\]at a point\[~C\].
\[AC:BC=\text{ }5:6\]