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Three bags contain a number of red and white balls as follows: Bag \[1:3\] red balls, Bag \[2:2\] red balls and \[1\] white ball Bag \[3:3\] white balls. The probability that bag i will be chosen and a ball is selected from it is \[\mathbf{i}/\mathbf{6},\text{ }\mathbf{i}\text{ }=\text{ }\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3}\]. What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?
Three bags contain a number of red and white balls as follows: Bag \[1:3\] red balls, Bag \[2:2\] red balls and \[1\] white ball Bag \[3:3\] white balls. The probability that bag i will be chosen and a ball is selected from it is \[\mathbf{i}/\mathbf{6},\text{ }\mathbf{i}\text{ }=\text{ }\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3}\]. What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?
CBSE | Class 12 | Exercise 1 | Maths | NCERT Exemplar | Probability
Three bags contain a number of red and white balls as follows: Bag \[1:3\] red balls, Bag \[2:2\] red balls and \[1\] white ball Bag \[3:3\] white balls. The probability that bag i will be chosen and a ball is selected from it is \[\mathbf{i}/\mathbf{6},\text{ }\mathbf{i}\text{ }=\text{ }\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3}\]. What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?

Given:

Bag \[1:3\] red balls,

Bag \[2:2\] red balls and \[1\] white ball

Bag \[3:3\]  white balls

Now, let E1, E2 and E3 be the events of choosing Bag \[1\], Bag \[2\] and Bag \[3\] respectively and a ball is drawn from it.

And, we have

\[P({{E}_{1}})\text{ }=\text{ }1/6,\text{ }P({{E}_{2}})\text{ }=\text{ }2/6\]and \[P({{E}_{3}})\text{ }=\text{ }3/6\]

Therefore, the required probabilities are \[7/18\] and \[11/18\].

i

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