Current flowing in the wires, $\mid=300 \mathrm{~A}$
Wires are separated by distance, $d=1.5 \mathrm{~cm}=0.015 \mathrm{~m}$
Length of the wires, $\mid=70 \mathrm{~cm}=0.7 \mathrm{~m}$
Force between the two wires, $F=\left.\mu_{0}\right|^{2} / 2 \pi d$
Here,
$\mu_{0}=$ permeability of the free space $=4 \pi \times 10^{-7} \mathrm{Tm} / \mathrm{A}$
$F=\frac{4 \pi \times 10^{-7} \times(300)^{2}}{2 \pi \times 0.015}=1.2 \mathrm{~N} / \mathrm{m}$
Because the wires’ directions are opposing, the force will be repelling.