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The value of \[\mathbf{sin}\text{ }(\mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}\left( \mathbf{0}.\mathbf{75} \right))\] is equal to (a) \[\mathbf{0}.\mathbf{75}\] (b) \[\mathbf{1}.\mathbf{5}\] (c) \[\mathbf{0}.\mathbf{96}\] (d) \[\mathbf{sin}\text{ }\mathbf{1}.\mathbf{5}\]
The value of \[\mathbf{sin}\text{ }(\mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}\left( \mathbf{0}.\mathbf{75} \right))\] is equal to (a) \[\mathbf{0}.\mathbf{75}\] (b) \[\mathbf{1}.\mathbf{5}\] (c) \[\mathbf{0}.\mathbf{96}\] (d) \[\mathbf{sin}\text{ }\mathbf{1}.\mathbf{5}\]
CBSE | Class 12 | Exercise 1 | Inverse Trigonometric Functions | Maths | NCERT Exemplar
The value of \[\mathbf{sin}\text{ }(\mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}\left( \mathbf{0}.\mathbf{75} \right))\] is equal to (a) \[\mathbf{0}.\mathbf{75}\] (b) \[\mathbf{1}.\mathbf{5}\] (c) \[\mathbf{0}.\mathbf{96}\] (d) \[\mathbf{sin}\text{ }\mathbf{1}.\mathbf{5}\]

The correct option is  (c) \[\mathbf{0}.\mathbf{96}\]

We have, \[sin\text{ }(2\text{ }ta{{n}^{-1}}\left( 0.75 \right))\]

i

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