Answer –
- We are given,
Mass of neon isotope – \[{}_{10}^{20}Ne\], m1 = 19.99 u
Abundance of neon isotope – \[{}_{10}^{20}Ne\], n1 = 90.51%
Mass of neon isotope – \[{}_{10}^{21}Ne\], m2 = 20.99 u
Abundance of neon isotope – \[{}_{10}^{21}Ne\], n2 = 0.27%
Mass of neon isotope – \[{}_{10}^{22}Ne\], m3 = 21.99 u
Abundance of neon isotope – \[{}_{10}^{22}Ne\], n3 = 9.22%
Average atomic mass of Neon is given by the relation –
\[m=\frac{{{\operatorname{m}}_{1}}{{n}_{1}}+{{m}_{2}}{{n}_{2}}+{{m}_{3}}{{n}_{3}}}{{{n}_{1}}+{{n}_{2}}+{{n}_{3}}}\]
\[m=\frac{19.99\times 90.51+20.99\times 0.27+21.99\times 9.22}{90.51+0.27+9.22}\]
\[m=20.1771u\]