Answer is (d) $2: 3$
Given:
$7 x^{2}-12 x+18=0$
$\therefore \alpha+\beta=\frac{12}{7}$ and $\beta=\frac{18}{7}$, where
$\alpha$ and $\beta$ are the roots of the equation
$\therefore$ Ratio of the sum and product of the roots $=\frac{12}{7}: \frac{18}{7}$
$=12: 18$
$=2: 3$