BC = √μrεr (CD-AE)
BC >0; CD > AE
-√μrεr AE = BC – √μrεr CD
BC = √μrεr (CD – AE)
AE > CD
Therefore, BC < 0
ii) BC = AC sin θi
CD – AE = AC sin θr
BC = √μrεr
AC sin θi = √μrεr AC sin θr
sin θi/sin θr = √μrεr
BC = √μrεr (CD-AE)
BC >0; CD > AE
-√μrεr AE = BC – √μrεr CD
BC = √μrεr (CD – AE)
AE > CD
Therefore, BC < 0
ii) BC = AC sin θi
CD – AE = AC sin θr
BC = √μrεr
AC sin θi = √μrεr AC sin θr
sin θi/sin θr = √μrεr