The number of different four digit numbers that can be formed with the digits 2, 3, 4, 7 and using each digit only once is A. 120 B. 96 C. 24 D. 100
The number of different four digit numbers that can be formed with the digits 2, 3, 4, 7 and using each digit only once is A. 120 B. 96 C. 24 D. 100

Solution:

Option (C) 24 is correct.

Explanation:

It is known that,

$\begin{array}{l}
{ }^{n} P_{r}= \\
\frac{n !}{(n-r) !}
\end{array}$

${ }^{4} \mathrm{P}_{4}=4 !=24$ is the four digit numbers that can be formed with the digits $2,3,4,7$ and using each digit only once.

As a result, Option (C) 24 is the correct answer.