Answer –
We are given the decay rate of living carbon-containing matter, R = 15 decay/min
Let N represent the number of radioactive atoms present in a normal carbon-containing matter.
Half- life of \[{}_{6}^{14}C\]is given by \[{{T}_{\frac{1}{2}}}\] = 5730 years
We are also given the decay rate of the specimen obtained from the Mohenjo-Daro site which is
R’ = 9 decays/min
Let N’ represent the number of radioactive atoms present during the Mohenjo-Daro period in the specimen.
We know that the relation between the decay constant, λ and time, t is given by:
\[\frac{N}{{{N}_{0}}}=\frac{R}{{{R}^{‘}}}={{e}^{-\lambda t}}\]
Where, λ = Decay constant and t represents Time. So, from the above two equations we have –
\[{{e}^{-\lambda t}}=\frac{9}{15}=\frac{3}{5}\]
\[-\lambda t=\log \left( \frac{3}{5} \right)=-0.5108\]
Using the relation –
\[-\lambda =\frac{0.693}{T}\]
We then have –
\[t=0.5108\times \frac{T}{0.693}=4223.5Tyears\]
Therefore, the approximate age of the Indus-Valley civilization is 4223.5 years.