The length of a second’s pendulum on the surface of the earth is 1 m. What will be the length of a second’s pendulum on the moon?

Answer:

We know that the expression for the time period of a simple pendulum is

T = 2π√l/g

Where l represents the length of the pendulum and,

g denotes the acceleration due to gravity

Therefore,

l_moon/g_moon = l_earth/gearth = 1/6 m