The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations: $E=h v, p=h / \lambda$.
But while the value of $\lambda$ is physically significant, the value of $v$ (and therefore, the value of the phase speed $\vee \lambda$ ) has no physical significance. Why?

3 years ago

Within the addictive constant, the absolute value of a particle’s energy is arbitrary. As a result, the wavelength $\lambda$ is relevant, but the electron’s frequency (v) has no direct physical importance. As a result, product v $\lambda$ has no physical meaning.