| Marks obtained | 5 | 6 | 7 | 8 | 9 | 10 |
| No. of students | 3 | 9 | 6 | 4 | 2 | 1 |
Solution:
We write the marks in cumulative frequency table.
| Marks x | Frequency (f) | fx | Cumulative frequency |
| 5 | 3 | 15 | 3 |
| 6 | 9 | 54 | 12 |
| 7 | 6 | 42 | 18 |
| 8 | 4 | 32 | 22 |
| 9 | 2 | 18 | 24 |
| 10 | 1 | 10 | 25 |
| Total | Ʃf = 25 | Ʃfx = 171 |
Mean = Ʃfx/Ʃf
= 171/25
= 6.84
Hence the mean is 6.84.
Here number of observation, n = 25 which is odd.
Median = ((n+1)/2)th term
= (25+1)/2
= 26/2
= 13th term
= 7
Hence the median is 7.
Here the frequency corresponding to 6 is maximum.
Hence the mode is 6.