Calculation:
3 molal solution of NaOH = 3 moles of NaOH dissolved in water
3 mole of NaOH = 120g
Density of solution = 1.110gmL-1
Volume = mass/density
Volume = 1120g/1.110gmL-1
Volume =1.009L
Hence,
Molarity of the solution = 3/1.009
Molarity of the solution = 2.97M