The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then (a) $Ee/Ep = 10^{-4}$ (b)$Ee/Ep = 10^{-2}$ (c) $Pe/me_c = 10^{-2}$ (d) $Pe/me_c = 10^{-4}$ contexto.120 3 years ago The correct answers are b) Ee/Ep = 10-2 c) Pe/mec = 10-2