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The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then (a) $Ee/Ep = 10^{-4}$ (b)$Ee/Ep = 10^{-2}$ (c) $Pe/me_c = 10^{-2}$ (d) $Pe/me_c = 10^{-4}$
The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then (a) $Ee/Ep = 10^{-4}$ (b)$Ee/Ep = 10^{-2}$ (c) $Pe/me_c = 10^{-2}$ (d) $Pe/me_c = 10^{-4}$
CBSE | Class 12 | Dual Nature of Radiation and Matter | ncert exemplar | Physics
The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then (a) $Ee/Ep = 10^{-4}$ (b)$Ee/Ep = 10^{-2}$ (c) $Pe/me_c = 10^{-2}$ (d) $Pe/me_c = 10^{-4}$

The correct answers are

b) Ee/Ep = 10-2

c) Pe/mec = 10-2

i

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