Answer:

Given,

d = 10

Sum of all angles in a quadrilateral = 360

Assume the angles are a – 3d, a – d, a + d, a + 3d

a – 2d + a – d + a + d + a + 2d = 360

4a = 360

a = 90… (i)

(a – d) – (a – 3d) = 10

2d = 10

d = 10/2

= 5

Hence, the angles are a – 3d, a – d, a + d, a + 3d which is 75^o, 85^o, 95^o, 105^o