$$
\begin{array}{l}
\text { Mean }=n p \\
\text { Variance }=n p(1-p)
\end{array}
$$
Therefore according to question
$$
\begin{array}{l}
1-\mathrm{p}=\mathrm{q}=\frac{\text { Variance }}{\text { Mean }}=\frac{2.25}{9}=0.25 \\
\mathrm{p}=1-0.25=0.75 \\
\mathrm{n}=\frac{\text { Mean }}{\mathrm{p}}=\frac{9}{0.75}=12
\end{array}
$$
Therefore Binomial Distribution $(\mathrm{n}, \mathrm{p}, 1-\mathrm{p})=(12, .75, .25)=\left(12, \frac{3}{4}, \frac{1}{4}\right)$