Solution:
From the question it is given that, \[2(2x+3)-10<6(x-2)\]
After multiplying we get
\[4x+6-10<6x-12\]
After simplifying we get
\[-4+12<6x-4x\]
\[8<2x\]
\[4<x\]
The solutions of \[2(2x+3)-10<6(x-2)\]are defined by all the real numbers greater than or equal to \[4\].
Therefore the required solution set is \[(4,-\infty )\]